Chemistry: The Central Science (13th Edition)

by Brown, Theodore E.; LeMay, H. Eugene; Bursten, Bruce E.; Murphy, Catherine; Woodward, Patrick; Stoltzfus, Matthew E.

Published by Prentice Hall

ISBN 10: 0321910419

ISBN 13: 978-0-32191-041-7

Chapter 5 - Thermochemistry - Exercises - Page 205: 5.39a

Answer

$C_2H_5OH + 3O_2 —> 3H_2O + 2CO_2, \Delta H = -1235 kJ$

Work Step by Step

You need to balance the equation first, then write the change in enthalpy after the completed equation. In this case ΔH is negative because the problem stated that it “releases” heat. $C_2H_5OH + 3O_2 —> 3H_2O + 2CO_2, \Delta H = -1235 kJ$

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