## Chemistry: The Central Science (13th Edition)

$Sr(OH)_2 + 2 HNO_3 --> Sr(NO_3)_2 + 2 H_2O$
1. Write the unbalanced equation: $Sr(OH)_2 + HNO_3 --> Sr(NO_3)_2 + H_2O$ 2. Balance the equation: * We will need to add a 2 next to $HNO_3$, because 1 $Sr(NO_3)_2$ has 2 $NO_3$. $Sr(OH)_2 + 2 HNO_3 --> Sr(NO_3)_2 + H_2O$ *Now, we can analize that, there are 2 $H^+$ reacting with 2 $OH^-$, which will form 2 water molecules$(H_2O)$. $Sr(OH)_2 + 2 HNO_3 --> Sr(NO_3)_2 + 2 H_2O$ *Now the equation is totally balanced.