Answer
Copper will be oxidized under standard conditions in the presence of Oxygen and Hydrogen. Half reaction equations are as under: -
$2Cu(s)+ 2H_{2}O(l) → 2CuO(s) + 4e^{-} + 4H^{+}(aq)$
$O_{2} (g) + 4e^{-} + 4H^{+} (aq) → 2H_{2}O (l)$
Work Step by Step
Given above