Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 20 - Electrochemistry - Exercises - Page 904: 20.78b


Anode half reaction is as under: - $Zn(s) + 2H_{2}O(l) → Zn(OH)_{2} (aq) + 2H^{+} + 2e^{-}$

Work Step by Step

Here Zn is acting as anode. It loses two electrons and reduces NiO(OH)
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