Answer
Anode half reaction is as under: -
$Zn(s) + 2H_{2}O(l) → Zn(OH)_{2} (aq) + 2H^{+} + 2e^{-}$
Work Step by Step
Here Zn is acting as anode. It loses two electrons and reduces NiO(OH)
Chemistry: The Central Science (13th Edition)
by Brown, Theodore E.; LeMay, H. Eugene; Bursten, Bruce E.; Murphy, Catherine; Woodward, Patrick; Stoltzfus, Matthew E.
Published by
Prentice Hall
ISBN 10:
0321910419
ISBN 13:
978-0-32191-041-7
Chapter 20 - Electrochemistry - Exercises - Page 904: 20.78b
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