Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 20 - Electrochemistry - Exercises - Page 903: 20.58

Answer

$n=1.996=2.00$

Work Step by Step

What is given... $\mathrm{T}=298 \mathrm{~K}$ $E_{\text {Cell }}=+0.17 \mathrm{~V}$ $K=5.5 \times 10^{5}$ $n=$ ? Formula... $E_{\text {Cell }}=\frac{R T}{n F} \ln (K)$ $n F E=R T \ln (K)$ $n=\frac{R T}{F E} \ln (K)$ $n=\frac{(8.314)(298)}{(96485)(0.17)} \ln \left(5.5 \times 10^{5}\right)$ $n=1.996=2.00$
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