Answer
$Cu^{2+} < O_{2} < Cr_{2}O_{7}^{2-} < Cl_{2} < H_{2}O_{2}$
Work Step by Step
Oxidizing strengths of each are given below:
$Cr_{2}O_{7}^{2-}: +1.33$
$H_{2}O_{2}: +1.776$
$Cu^{2+}: 0.337$
$Cl_{2}: +1.359%$
$O_{2}: +1.23$
Chemistry: The Central Science (13th Edition)
by Brown, Theodore E.; LeMay, H. Eugene; Bursten, Bruce E.; Murphy, Catherine; Woodward, Patrick; Stoltzfus, Matthew E.
Published by
Prentice Hall
ISBN 10:
0321910419
ISBN 13:
978-0-32191-041-7
Chapter 20 - Electrochemistry - Exercises - Page 902: 20.47a
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