Answer
Compound 1: $0.749 \frac{g \space F}{g \space I}$
Compound 2: $0.449 \frac{g \space F}{g \space I}$
Compound 3: $1.05 \frac{g \space F}{g \space I}$
Work Step by Step
First compound:
$\frac{mass \space of \space fluorine (g)}{mass \space of \space iodine(g)} = \frac{3.56 \space g \space F}{4.75 \space g \space I} = 0.749 \frac{g \space F}{g \space I}$
Second compound:
$\frac{mass \space of \space fluorine (g)}{mass \space of \space iodine(g)} = \frac{3.43 \space g \space F}{7.64 \space g \space I} = 0.449\frac{g \space F}{g \space I}$
Third compound:
$\frac{mass \space of \space fluorine (g)}{mass \space of \space iodine(g)} = \frac{9.86 \space g \space F}{9.41 \space g \space I} = 1.05 \frac{g \space F}{g \space I}$
