## Chemistry: The Central Science (13th Edition)

1. Find the pOH of the solution. pH + pOH = 14 12.08 + pOH = 14 pOH = 1.92 2. Now, find the concentration of $O^{}H^{-}$ in the solution. $[O^{}H^{-}]$ = $10^{-pOH}$ $[O^{}H^{-}]$ = $10^{-1.92}$ $[O^{}H^{-}]$ $\approx$ 0.012 3. Because we have 1 OH in 1 KOH, we can assume that the concentration of KOH is about 0.012 mol/L.