Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 16 - Acid-Base Equilibria - Exercises: 16.4b

Answer

Approximately 0.012 mol/L.

Work Step by Step

1. Find the pOH of the solution. pH + pOH = 14 12.08 + pOH = 14 pOH = 1.92 2. Now, find the concentration of $O^{}H^{-}$ in the solution. $[O^{}H^{-}]$ = $10^{-pOH}$ $[O^{}H^{-}]$ = $10^{-1.92}$ $[O^{}H^{-}]$ $\approx$ 0.012 3. Because we have 1 OH in 1 KOH, we can assume that the concentration of KOH is about 0.012 mol/L.
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