Answer
$2H_{2}O_{2}\rightarrow 2H_{2}O + O_{2}$
Work Step by Step
To write the balanced equation for the overall reaction, cancel out intermediates and molecules that are products in one step of the reaction and reactants in another step. In this case, $IO^{-}$ and $I^{-}$ are canceled out. This leaves 2 molecules of $H_{2}O_{2}$ as the reactant and 2 molecules of $H_{2}O$ and 1 molecule of $O_{2}$ as the products.
