Answer
$7.11\times10^3 M^{-2}s^{-1}$
Work Step by Step
From 14.36b, we have:
$rate=k[NO]^2[O_2]$
To find the value of the rate constant, simply rewrite the above equation as:
$k=\frac{rate}{[NO]^2[O_2]}$
Experiment 1:
$k=\frac{rate}{[NO]^2[O_2]}=\frac{1.41\times10^{-2}}{0.0126^2\times0.0125}=7.11\times10^3 M^{-2}s^{-1}$
Experiment 2:
$k=\frac{rate}{[NO]^2[O_2]}=\frac{5.64\times10^{-2}}{0.0252^2\times0.0125}=7.11\times10^3 M^{-2}s^{-1}$
Experiment 3:
$k=\frac{rate}{[NO]^2[O_2]}=\frac{1.13\times10^{-1}}{0.0252^2\times0.0250}= M^{-2}s^{-1}=7.12\times10^3M^{-2}s^{-1}$
Thus, the average of these constants, rounded to 2 decimal digits, is $7.11\times10^3 M^{-2}s^{-1}$
