Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 10 - Gases - Exercises - Page 434: 10.24b


$7.61\times10^2\ torr$

Work Step by Step

$P_{gas}=P_{atm}+12.3\ torr=(0.985\ atm\times\frac{760\ torr}{1\ atm})+12.3\ torr=760.9\ torr=7.61\times10^2\ torr$
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