Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 1 - Introduction: Matter and Measurement - Exercises - Page 37: 1.58


There can be obtained 565 ft of copper from that ingot.

Work Step by Step

1. First we need to find the total volume of copper. - Identify the conversion factors: Pounds to grams: $\frac{453.6 \space g}{1 \space lb}$ Now we can convert the weight of copper to grams and use the density to find the volume in $cm^3$. 2. Now we need to convert the volume of copper into feet of copper wire. - Identify the conversion factors: Centimeters to feet: $\frac{1 \space ft}{30.48 \space cm}$ Volume of the cylinder to length\height: $\frac{h (cm)}{\pi r^2 h(cm^3)} = \frac{1 \space cm}{\pi (d/2)^2 \space cm^3}$ ** d = 7.50 mm $\times \frac{100 \space cm}{1000 \space mm} = 0.750 \space cm$ 3. Calculate the length\height of the wire: $150 \space lb \times \frac{453.6 \space g}{1 \space lb} \times \frac{1 \space cm^3}{8.94 \space g} \times \frac{1 \space cm}{\pi (0.750/2)^2 \space cm^3} \times \frac{1 \space ft}{30.48 \space cm} = 565 \space ft$
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