## Chemistry: Principles and Practice (3rd Edition)

Published by Cengage Learning

# Chapter 7 - Electronic Structure - Questions and Exercises - Exercises - Page 288: 7.90

#### Answer

Frequency (ν) = $4.68\times10^{14}$ Hz Energy (E) = $3.10\times10^{-19}J$

#### Work Step by Step

ν = c/λ c = $2.997925\times10^{8}ms^{-1}$ λ = 641 nm = $641\times10^{-9}m$ ν = $\frac{2.997925\times10^{8}ms^{-1}}{641\times10^{-9}m}$ = $4.68\times10^{14}s^{-1}$ E = hν h = $6.626\times10^{-34}Js$ ν = $4.68\times10^{14}s^{-1}$ E = $6.626\times10^{-34}Js\times4.68\times10^{14}s^{-1}$ = $3.10\times10^{-19}J$

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