Chemistry: Principles and Practice (3rd Edition)

Published by Cengage Learning
ISBN 10: 0534420125
ISBN 13: 978-0-53442-012-3

Chapter 7 - Electronic Structure - Questions and Exercises - Exercises: 7.47

Answer

2650 m/s

Work Step by Step

λ = $\frac{h}{mv}$ Or velocity, v = $\frac{h}{mλ}$ h = $6.626\times10^{-34}Js$ m = $1.67\times10^{-27} kg$ λ = 0.150 nm = $0.150\times10^{-9}m$ v = $\frac{6.626\times10^{-34}Js}{1.67\times10^{-27} kg\times0.150\times10^{-9}m}$ = 2650 m
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