Answer
(a) Sr(NO$_3$)$_2$
(b) NaH$_2$PO$_4$
(c) KClO$_4$
(d) LiHSO$_4$
Work Step by Step
(a) Sr(NO$_3$)$_2$
Strontium (Sr) is an alkaline earth metal and has a valence of 2+. We refer to the table of polyatomic anions (Table 2.2) on page 65 of the book to find the formula and charge for nitrate (NO$_3$$^-$). We will need one strontium ion for every two nitrate ions to balance the charges in this compound.
(b) NaH$_2$PO$_4$
Sodium (Na) is an alkali metal and has a valence of 1+. We refer to the table of polyatomic anions (Table 2.2) on page 65 of the book to find the formula and charge for dihydrogen phosphate (H$_2$PO$_4$$^-$). We will need one sodium ion for every one dihydrogen phosphate ion to balance the charges in this compound.
(c) KClO$_4$
Potassium (K) is an alkali metal and has a valence of 1+. We refer to the table of polyatomic anions (Table 2.2) on page 65 of the book to find the formula and charge for perchlorate (ClO$_4$$^-$). We will need one potassium ion for every one perchlorate ion to balance the charges in this compound.
(d) LiHSO$_4$
Lithium (Li) is an alkali metal and has a valence of 1+. We refer to the table of polyatomic anions (Table 2.2) on page 65 of the book to find the formula and charge for hydrogen sulfate (HSO$_4$$^-$). We will need one lithium ion for every one hydrogen sulfate ion to balance the charges in this compound.