Answer
$2 CH_3COOH \lt -- \gt CH_3COO{H_2}^+ + CH_3COO^-$
Work Step by Step
- In autoionization reactions, we have 2 molecules of an amphoteric substance, where one of them is going to react as an acid, and the other as a base.
- Therefore, one of the molecules is going to donate a proton ($CH_3COO^-$), and the other is going to receive one ($CH_3COO{H_2}^+$)