Chemistry: Principles and Practice (3rd Edition)

Published by Cengage Learning
ISBN 10: 0534420125
ISBN 13: 978-0-53442-012-3

Chapter 1 - Introduction to Chemistry - Questions and Exercises - Exercises - Page 37: 1.84

Answer

a) $258.8^{\circ}F$, $399.15 K$ b) $177^{\circ}C$

Work Step by Step

a) In converting from Celsius to Fahrenheit, the formula is $$T(^{\circ}F)=\frac{9}{5}\times T(^{\circ}C)+32$$ Substituting, $$T(^{\circ}F)=\frac{9}{5}\times (126)+32$$ $$T(^{\circ}F)=226.8+32$$ $$T(^{\circ}F)=258.8^{\circ}F$$ Converting temperature from Celsius to Kelvin, we use the formula $$T(K)=T(^{\circ}C)+273.15$$ Substituting, $$T(K)=126+273.15$$ $$T(K)=399.15 K$$ b) In converting from Fahrenheit to Celsius, the formula is $$T(^{\circ}C)=\frac{5}{9}\times(T(^{\circ}F)-32)$$ Substituting, $$T(^{\circ}C)=\frac{5}{9}\times(350-32)$$ $$T(^{\circ}C)=\frac{5}{9}\times(318)$$ $$T(^{\circ}C)=177^{\circ}C$$
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