#### Answer

$$4.3 \times 10^{12} atoms$$

#### Work Step by Step

We use stoichiometry to find: $$ \frac{1 g}{1} \times \frac{1 mol}{14 g} \times \frac{6.022 \times 10^{23} atom}{mol} \times \frac {1 \ impure \ atom}{10^{10} atoms} \\= 4.3 \times 10^{12} atoms$$