Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 9 - Liquids, Solids, and Materials - Problem Solving Practice 9.1 - Page 375: a


9.83 kJ

Work Step by Step

Number of moles of $C_{6}H_{6}=\frac{25.0\,g}{78.11\,g/mol}$ $=0.320\,mol$ 30.72 kJ is needed to vaporize 1 mol of $C_{6}H_{6}$ at 1 bar pressure and at its boiling point. $\implies$ heat transfer required= $0.320\,mol\times 30.72\,kJ/mol=9.83\,kJ$
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