## Chemistry: The Molecular Science (5th Edition)

Number of moles of $C_{6}H_{6}=\frac{25.0\,g}{78.11\,g/mol}$ $=0.320\,mol$ 30.72 kJ is needed to vaporize 1 mol of $C_{6}H_{6}$ at 1 bar pressure and at its boiling point. $\implies$ heat transfer required= $0.320\,mol\times 30.72\,kJ/mol=9.83\,kJ$