## Chemistry: The Molecular Science (5th Edition)

Using the data from problem solving example 8.8 and applying ratio of coefficients formula, we have: $n_{Na}$ = 2.46 mol N2 x 2 mol Na / 3 mol N2 = 1.64 mol Na $n_{KNO3}$ = 1.64 mol Na x 2 mol KNO3 / 10 mol Na = 0.328 mol KNO3 $m_{KNO3}$= 0.328 mol KNO3 x 101.1 g KNO3 / 1 mol KNO3 = 33.2 g KNO3 $n_{additional N2}$ = 1.64 mol Na x 1 mol N2 / 10 mol Na = 0.164 mol N2