Answer
Minimum mass of KNO3 = 33.2 g
Additional volume of N2 = 0.164 mol
Work Step by Step
Using the data from problem solving example 8.8 and applying ratio of coefficients formula, we have:
$n_{Na}$ = 2.46 mol N2 x 2 mol Na / 3 mol N2 = 1.64 mol Na
$n_{KNO3}$ = 1.64 mol Na x 2 mol KNO3 / 10 mol Na = 0.328 mol KNO3
$m_{KNO3}$= 0.328 mol KNO3 x 101.1 g KNO3 / 1 mol KNO3 = 33.2 g KNO3
$n_{additional N2}$ = 1.64 mol Na x 1 mol N2 / 10 mol Na = 0.164 mol N2
