Answer
$ 1312 kJ/ mol-photon $
Work Step by Step
We find:
$\frac{2.179 \times 10^{-18}J}{1 photon} \times \frac{6.022 \times 10^{23} photon}{1 mol -photons} \times \frac{1 kJ}{1000 J} = 1312 kJ/ mol-photon $
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 5 - Electron Configurations and the Periodic Table - Conceptual Exercise 5.6 - Conversions - Page 203: a
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
