Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 4 - Energy and Chemical Reactions - Questions for Review and Thought - Topical Questions - Page 189e: 76c


$1 N_2(g) + {2}H_2(g) + \frac{3}{2} O_2(g)-- \gt NH_4NO_3(s)$ $\Delta_fH^{\circ}\{NH_4NO_3(s)\} = -365.56kJ/mol$

Work Step by Step

1. Write the separated atoms, and their coefficients, to form a single $NH_4NO_3$ $2N + 4H + 3O -- \gt NH_4NO_3$ 2. Analyze the appendix J, and find the standard state for each element: - Hint: It is the compound with $\Delta_fH^{\circ}$ = 0. - Divide the coefficient by the number of atoms in each compound in standard state: $\frac{2}{2} N_2(g) + \frac{4}{2}H_2(g) + \frac{3}{2} O_2(g)-- \gt NH_4NO_3(s)$ Just add the $\Delta_fH^{\circ}$** after the reaction. ** Appendix J. $1 N_2(g) + {2}H_2(g) + \frac{3}{2} O_2(g)-- \gt NH_4NO_3(s)$ $\Delta_fH^{\circ}\{NH_4NO_3(s)\} = -365.56kJ/mol$
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