#### Answer

$132\,J\,mol^{-1}K^{-1}$

#### Work Step by Step

Molar heat capacity=
$0.861\,J\,g^{-1}K^{-1}\times \frac{153.82\,g\,CCl_{4}}{1\,mol\,CCl_{4}}$
$= 132\,J\,mol^{-1}K^{-1}$

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Published by
Cengage Learning

ISBN 10:
1285199049

ISBN 13:
978-1-28519-904-7

$132\,J\,mol^{-1}K^{-1}$

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