Answer
$Ba^{2+}(aq) + SO_{4}^{2−}(aq) → BaSO_{4}(s)$
Work Step by Step
We find:
$BaCl_{2}(aq) + Na_{2}SO_{4}(aq) → BaSO_{4}(s) + 2 NaCl(aq)$
Thus, the net ionic equation is:
$Ba^{2+}(aq) + SO_{4}^{2−}(aq) → BaSO_{4}(s)$
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