Answer
The mass of $5.00 \times 10^{-3}$ mol sucrose is equal to 1.71 g.
Work Step by Step
Calculate the molar mass for sucrose: $(C_{12}H_{22}O_{11})$
12.01* 12 + 1.01* 22 + 16.00* 11 = 342.34g/mol
Now, find the mass in $5.00 \times 10^{-3}$ moles:
$5.00 \times 10^{-3}$ mol $ \times \frac{342.34g}{ 1mol} = 1.71g$
