## Chemistry: The Molecular Science (5th Edition)

The mass of $5.00 \times 10^{-3}$ mol sucrose is equal to 1.71 g.
Calculate the molar mass for sucrose: $(C_{12}H_{22}O_{11})$ 12.01* 12 + 1.01* 22 + 16.00* 11 = 342.34g/mol Now, find the mass in $5.00 \times 10^{-3}$ moles: $5.00 \times 10^{-3}$ mol $\times \frac{342.34g}{ 1mol} = 1.71g$