Answer
$_{92}^{295}U + _{0}^{1}n → _{54}^{140}Xe + _{38}^{93}Sr + 3 \space _{0}^{1}n$
Work Step by Step
U-295 reacts with 1 neutron to form Xe-140 and Sr-93 along with 3 neutrons.
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 18 - Nuclear Chemistry - Questions for Review and Thought - Topical Questions - Page 817c: 55a
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