Answer
$^{237}_{93}Np → ^{4}_{2}He + ^{233}_{91}Pa$
Work Step by Step
Np-237 undergoes alpha decay to form Pa-233. Thus, we find:
$$^{237}_{93}Np → ^{4}_{2}He + ^{233}_{91}Pa$$
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 18 - Nuclear Chemistry - Problem Solving Practice 18.1 - Page 788: a
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