Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 18 - Nuclear Chemistry - Problem Solving Practice 18.1 - Page 788: a


$^{237}_{93}Np → ^{4}_{2}He + ^{233}_{91}Pa$

Work Step by Step

Np-237 undergoes alpha decay to form Pa-233. Thus, we find: $$^{237}_{93}Np → ^{4}_{2}He + ^{233}_{91}Pa$$
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