Answer
Yes.
Work Step by Step
The more positive the value of E°, more easily the substance on the left-hand side of the half-reaction can be reduced. The more negative the value of E°, the more easily the substance on the right-hand side can be oxidised. Therefore, Co(s) which is on the right-hand side of the half-reaction with E° value= -0.277 can easily reduce $Pt^{2+}$ which is on the left-hand side of the half-reaction with E° value=1.118
