Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 16 - Thermodynamics: Directionality of Chemical Reactions - Problem Solving Practice 16.3 - Page 706: b

Answer

$43.4\,JK^{-1}mol^{-1}$

Work Step by Step

$\Delta S^{\circ}_{rxn}=\Sigma n_{p}S^{\circ}(products)-\Sigma n_{r}S^{\circ}(reactants)$ $=[S^{\circ}(NaCl,aq)]-[S^{\circ}(NaCl,s)]$ $=(115.5\,JK^{-1}mol^{-1})-(72.13\,JK^{-1}mol^{-1})$ $=43.4\,JK^{-1}mol^{-1}$ $\Delta S^{\circ}_{rxn}$ is positive because of the increase in entropy.
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