Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 14 - Acids and Bases - Exercise 14.4 - HSO(4) as a Base - Page 611: b


First pair: $HS{O_4}^-$: Base; $H_2SO_4$: Conjugate acid. Second pair: $H_2O$: Acid; $OH^-$: Conjugate acid.

Work Step by Step

As we wrote in the question above, the reaction for $HS{O_4}^-$ acting as a base is: $H{SO_4}^-(aq) + H_2O(l) \lt -- \gt H_2SO_4(aq) + OH^-(aq)$ - Identify the conjugate acid-base pairs of this reaction: 1. Identify the base and the acid in the reactants: - $HS{O_4}^-$ is turning into $H_2SO_4$; So it is gaining a proton. Therefore: $H{SO_4}^-$ is a base, and $H_2SO_4$ is its conjugate acid. - $H_2O$ is turning into $OH^-$; So it is losing a proton. Therefore: $H_2O$ is an acid, and $OH^-$ is its conjugate base.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.