# Chapter 14 - Acids and Bases - Exercise 14.10 - pOH and pH - Page 620: a

These solutions are equally basic. First solution: $[H_3O^+] = 3.16 \times 10^{-6}M$ Second solution: $[H_3O^+] = 3.16 \times 10^{-6}M$

#### Work Step by Step

- Let's call the first solution by: (a), and the other by (b). - To determine which one is more basic, compare the pOH of each one, the one with the lowest pOH is more basic. (a) pOH + pH = 14 pOH + 5.5 = 14 pOH = 14 - 5.5 = 8.5 (b) pOH = 8.5 - Since they have the same pOH, they are equally basic. - Now, calculate the $[H_3O^+]$: (a) $[H_3O^+] = 10^{-pH} = 10^{-5.5} = 3.16 \times 10^{-6}M$ (b) pH + pOH = 14 pH + 8.5 = 14 pH = 14 - 8.5 = 5.5 $[H_3O^+] = 10^{-pH} = 10^{-5.5} = 3.16 \times 10^{-6}M$

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