Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 11 - Chemical Kinetics: Rates of Reactions - Problem Solving Practice 11.2 - Page 480: b


$$ \frac{\Delta [NO_2]}{\Delta t} =0.015 \space mol \space L^{-1} \space s^{-1}$$

Work Step by Step

$$Rate = - \frac{1}{4}\frac{\Delta [NO_2]}{\Delta t} = - \frac{1}{1} \frac{\Delta [O_2]}{\Delta t}$$ Multiplying both sides by -4: $$ \frac{\Delta [NO_2]}{\Delta t} = 4 \times \frac{\Delta [O_2]}{\Delta t}$$ $$ \frac{\Delta [NO_2]}{\Delta t} = 4 \times (0.0037 \space mol \space L^{-1} \space s^{-1}) = 0.015 \space mol \space L^{-1} \space s^{-1}$$
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