Answer
Mass of silver: 0.7527g
Mass of chlorine: 0.2473g
Mass of iodine: 0.8853g
Work Step by Step
(Mass of silver) + (Mass of chlorine) = 1.0000g
(Mass of silver) + (Mass of iodine) = 1.6381g
It is given that the mass of iodine is 3.580 times the mass of chlorine per atom. Since the product has 1 atom of iodine per atom of chlorine in the reactant, we can rewrite the second equation as:
(Mass of silver) + 3.580(Mass of chlorine) = 1.6381g
Then use elimination to solve this system of equations. Subtract the first equation from the second:
(Mass of silver) + 3.580(Mass of chlorine) - ((Mass of silver) + (Mass of chlorine)) = 1.6381g - 1.0000g
2.580(Mass of chlorine) = 0.6381g
Mass of chlorine = 0.2473g
Use the given relations to find the masses of the other elements.
(Mass of silver) + 0.2473g = 1.0000g
Mass of silver = 0.7527g
Mass of iodine = 3.580(0.2473g) = 0.8853g
