Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 1 - The Nature of Chemistry - Questions for Review and Thought - More Challenging Questions - Page 41h: 111


Mass of silver: 0.7527g Mass of chlorine: 0.2473g Mass of iodine: 0.8853g

Work Step by Step

(Mass of silver) + (Mass of chlorine) = 1.0000g (Mass of silver) + (Mass of iodine) = 1.6381g It is given that the mass of iodine is 3.580 times the mass of chlorine per atom. Since the product has 1 atom of iodine per atom of chlorine in the reactant, we can rewrite the second equation as: (Mass of silver) + 3.580(Mass of chlorine) = 1.6381g Then use elimination to solve this system of equations. Subtract the first equation from the second: (Mass of silver) + 3.580(Mass of chlorine) - ((Mass of silver) + (Mass of chlorine)) = 1.6381g - 1.0000g 2.580(Mass of chlorine) = 0.6381g Mass of chlorine = 0.2473g Use the given relations to find the masses of the other elements. (Mass of silver) + 0.2473g = 1.0000g Mass of silver = 0.7527g Mass of iodine = 3.580(0.2473g) = 0.8853g
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