## Chemistry: Molecular Approach (4th Edition)

a) The elctronegativity difference between $I$ and $I$ is zero. So, the bond is pure covalent b) The elctronegativity difference between $Cs(0,7)$ and $Br(2.8)$ is $2.1$. So, the bond is ionic. c) The elctronegativity difference between $P(2.1)$ and $O(3.5)$ is $1.4$. So, the bond is polar covalent (See table 9.1 and figure 9.8)