Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 8 - Section 8.4 - Electron Configurations, Valence Electrons, and the Periodic Table - For Practice: 8.3

Answer

The electronic configuration of $P$ is $1s^22s^22p^63s^23p^3$ or $[Ne] 3s^23p^3$. The 5 electrons in the $3s^23p^3$ orbitals are the valence electrons. The 10 electrons in the $1s^22s^22p^6$ orbitals are the core electrons.

Work Step by Step

$P$ has 15 electrons. It has 5 more electrons than its previous noble gas, $Ne$. The electrons are distributed in the orbitals to get the electronic configuration as : $1s^22s^22p^63s^23p^3$ or $[Ne] 3s^23p^3$. The 5 electrons in the $3s^23p^3$ orbitals (outermost orbital) are the valence electrons. The 10 electrons in the $1s^22s^22p^6$ orbitals are the core electrons.
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