Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 7 - Exercises: 62

Answer

d. 2d

Work Step by Step

Here n =2, so possible values of l can be 0 or 1, which corresponds to s and p orbitals respectively. Hence for n=2, there cannot be a d orbital, because d corresponds to l=2.
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