Answer
We should use 0.105 L of that 6.00M solution.
Work Step by Step
1. Find the necessary volume
:
$C_1 * V_1 = C_2 * V_2$
$ 1.20 M * 0.525 L = 6 M* V_2$
$ 0.630 M*L = 6 M* V_2$
$V_2 = \frac{0.630 M*L}{6M}$
$V_2 = 0.105 L$
Chemistry: Molecular Approach (4th Edition)
by Tro, Nivaldo J.
Published by
Pearson
ISBN 10:
0134112830
ISBN 13:
978-0-13411-283-1
Chapter 4 - Section 4.4 - Solution Concentration and Solution Stoichiomentry - For More Practice - Page 156: 4.7
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