## Chemistry: Molecular Approach (4th Edition)

** 1 kg = 1000g $16kg \times \frac{1000g}{1kg} = 16 \times 10^{3}g$ 1. Calculate the number of moles of $NO_2$: 14.01* 1 + 16* 2 = 46.01g/mol $16\times 10^{3}g \times \frac{1 mol}{ 46.01g} = 347.8mol (NO_2)$ According to the balanced equation: The ratio of $NO_2$ to $HNO_3$ is 4 to 4: $347.8 mol (NO_2) \times \frac{ 4 mol(HNO_3)}{ 4 mol (NO_2)} = 347.8mol (HNO_3)$ 2. Calculate the mass of $HNO_3$: 1.008* 1 + 14.01* 1 + 16* 3 = 63.02g/mol $347.8 mol \times \frac{ 63.02 g}{ 1 mol} = 2.2\times 10^{4}g (HNO_3)$ $2.2 \times 10^4 g \times \frac{1kg}{1000g} = 22kg$