## Chemistry: Molecular Approach (4th Edition)

The molarity of this $C_2H_6O_2$ solution is equal to 3.32 M.
1. Calculate the molar mass: $C_2H_6O_2$ : ( 1.008 $\times$ 6 )+ ( 12.01 $\times$ 2 )+ ( 16.00 $\times$ 2 )= 62.07 g/mol 2. Use the information as conversion factors to find the molarity of this solution: $$\frac{ 20.0 g \space C_2H_6O_2 }{100 \space g \space solution} \times \frac{1 \space mol \space C_2H_6O_2 }{ 62.07 \space g \space C_2H_6O_2 } \times \frac{ 1.03 \space g \space solution}{1 \space mL \space solution} \times \frac{1000 \space mL}{1 \space L} = 3.32 \space M$$