## Chemistry: Molecular Approach (4th Edition)

Published by Pearson

# Chapter 3 - Section 3.9 - Composition of Compounds - For Practice - Page 110: 3.14

#### Answer

The percent composition of oxygen in acetic acid is equal to $53.29\%$.

#### Work Step by Step

1. Calculate the molar mass of: $C_2H_4O_2$: Molar Mass ($C_2H_4O_2$): 12.01* 2 + 1.008* 4 + 16.00* 2 = 60.05g/mol 2. Calculate the total mass of $O$ in one mole of this compound: Total Mass ($O$): $2 \times 16.00 = 32.00$ 3. Find the mass percent composition: $\frac{Total-mass (O)}{Molar-Mass} \times 100\% = \frac{ 32.00}{ 60.05} \times 100\% = 53.29\%$

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