Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 3 - Section 3.5 - Ionic Compounds: Formulas and Names - For More Practice - Page 99: 3.5

Answer

The compound has the formula $Rb_2S$

Work Step by Step

The cation is rubidium ($Rb^+$). The anion is from sulfur, which becomes $sulfide$ ($S^{2-}$). So, to balance the charges, two rubidium ions react with one sulfide ion. Hence, the compound has the formula $Rb_2S$
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