Chemistry: Molecular Approach (4th Edition)

a) $CaCO_3$ is an inorganic compound because carbonates are considered to be inorganic. b) $C_4H_8$ is an organic compound because it is made up of carbon, & hydrogen. c)$C_4H_6O_6$ is an organic compound because it is made up of carbon, oxygen, & hydrogen. d) $LiF$ is an inorganic compound because it does not contain carbon.