Answer
$9.0\times10^{13}\,J$
Work Step by Step
Energy $E=mc^{2}$ where $m$ is the mass and $c$ is the speed of light.
$\implies E= (0.0010\,kg)(3.00\times10^{8}\,m/s)^{2}$
$=9.0\times10^{13}\,J$
Chemistry: Molecular Approach (4th Edition)
by Tro, Nivaldo J.
Published by
Pearson
ISBN 10:
0134112830
ISBN 13:
978-0-13411-283-1
Chapter 20 - Exercises - Page 974: 65
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