## Chemistry: Molecular Approach (4th Edition)

7.33 x 10$^{3}$ electrons
A nucleon has a mass of 1.67 x 10$^{-21}$ kg and an electron has a mass of 9.11 x 10$^{-31}$ kg. Use these as conversion factors in order to determine the number of electrons required. = $4 nucleon \times \frac{1.67 \times 10^{-21} kg}{1 nucleon} \times \frac{1 electron}{9.11 \times 10^{-31} kg}$ = 7.33 x 10$^{3}$ electrons