Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 16 - Section 16.7 - Base Solutions - Chemistry and Medicine - Page 750: 1


$$Al(OH)_3(aq) + 3HCl(aq) \longrightarrow AlCl_3(aq) + 3 H_2O(l)$$ $$Mg(OH)_2(aq) + 2HCl(aq) \longrightarrow MgCl_2(aq) + 2 H_2O(l)$$ $$CaC{O_3}(aq) + 2HCl(aq) \longrightarrow CaCl_2(aq) + H_2CO_3(aq)$$

Work Step by Step

1. Find the amount of HCl necessary to react with one mol of each antacid. (a) Has 3 $OH^-$: Needs 3 $H^+$ (b) Has 2 $OH^-$: Needs 2 $H^+$ (c) Has 1 $C{O_3}^{2-}$: Needs 2 $H^+$ in order to neutralize it. 2. Write the products. The first one is a salt made of the metal in the antacid and chloride ion, and the second one is the conjugate acid of the reaction.
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