Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 15 - Exercises - Page 715: 35

Answer

The equilibrium constant at this temperature is equal to $136$

Work Step by Step

1. The exponent of each concentration is equal to its balance coefficient. $$K_C = \frac{[Products]}{[Reactants]} = \frac{[ CH_3OH ]}{[ CO ][ H_2 ] ^{ 2 }}$$ 2. Substitute the values and calculate the constant value: $$K_C = \frac{( 0.185 )}{( 0.105 )( 0.114 )^{ 2 }} = 136$$
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