Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 1 - Self-Assessment Quiz - Page 34: Q13


D) $9.75g/cm^{3}$

Work Step by Step

$1.796 kg\times/1000=1796 g$ $1796 g\div/ 4/3π(3.53)^3$
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