Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 1 - Exercises - Page 39: 70


The mass of acetone is 22.4g.

Work Step by Step

The mass, of liquid (acetone) is calculated as $mass = density \times volume$ Before substituting the values of density and volume into the above equation, convert the given volume from milliliters to cubic centimeters. To convert to mL to $cm^3$, first write the correct conversion factor using the following relationship: $1 cm^3 = 1 mL$ $28.56 mL = 28.56 cm^3$ Hence, the volume of acetone is $28.56 cm^3$ Substitute $0.7857 g/cm^3$ for $d$ and $28.56 cm^3$ for $V$ in the above expression, thus, $m = ( 0.7857 g/cm^3 ) x 28.56 cm^3$ $ = 22.4 g$
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