Answer
0.24 L
Work Step by Step
Volume of solution in litres = (Mass of $AgNO_{3}\div$Molar mass)/Molarity = $\frac{10. g\div169.87gmol^{-1}}{0.25molL^{-1}}$ = 0.24 L
Chemistry: Atoms First (2nd Edition)
by Zumdahl, Steven S.; Zumdahl, Susan A.
Published by
Cengage Learning
ISBN 10:
1305079248
ISBN 13:
978-1-30507-924-3
Chapter 6 - Exercises - Page 281c: 36
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