Chemistry: Atoms First (2nd Edition)

Published by Cengage Learning
ISBN 10: 1305079248
ISBN 13: 978-1-30507-924-3

Chapter 4 - Exercises - Page 197e: 64

Answer

The correct answer is option b: $Be_{2}, B_{2}, Ne_{2}$. The molecular orbital (MO) model predicts the stability of diatomic species based on the filling of the available molecular orbitals. The stability of a diatomic species is determined by the net bond order, which is the difference between the number of bonding and antibonding electrons.

Work Step by Step

a. $N_{2}^{2-}, O_{2}^{2-}, F_{2}^{2-}$: These species are not predicted to be stable by the MO model. The addition of extra electrons to the neutral diatomic molecules (N$_2$, O$_2$, F$_2$) would result in a net antibonding configuration, leading to instability. b. $Be_{2}, B_{2}, Ne_{2}$: These species are predicted to be stable by the MO model: - $Be_{2}$ has a net bond order of 1, making it a stable diatomic species. - $B_{2}$ has a net bond order of 1, making it a stable diatomic species. - $Ne_{2}$ has a net bond order of 0, which corresponds to a stable non-bonding configuration. Therefore, the diatomic species predicted to be stable by the molecular orbital model are $Be_{2}, B_{2}, Ne_{2}$.
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